3(2z+1)-4(z+2)=

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Solution for 3(2z+1)-4(z+2)= equation:


3 (2z+1)-4 (z+2)=0

We simplify the equation to the form, which is simple to understand 
3(2z+1)-4(z+2)=0

Reorder the terms in parentheses
+(+6z+3)-4*(z+2)=0

Remove unnecessary parentheses
+6z+3-4+*(+z+2+)=0

Reorder the terms in parentheses
+6z+3+(-4z-8)=0

Remove unnecessary parentheses
+6z+3-4z-8=0

We move all terms containing z to the left and all other terms to the right. 
+6z-4z=0-3+8

We simplify left and right side of the equation. 
+2z=+5

We divide both sides of the equation by 2 to get z. 
z=2.5

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