3(2z+-1)+5=5(z+1)

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Solution for 3(2z+-1)+5=5(z+1) equation: 



3(2z+-1)+5=5(z+1)

We move all terms to the left:

3(2z+-1)+5-(5(z+1))=0

We add all the numbers together, and all the variables

3(2z-1)-(5(z+1))+5=0

We multiply parentheses

6z-(5(z+1))-3+5=0



We calculate terms in parentheses: -(5(z+1)), so:

5(z+1)

We multiply parentheses

5z+5

Back to the equation:

-(5z+5)



We add all the numbers together, and all the variables

6z-(5z+5)+2=0

We get rid of parentheses

6z-5z-5+2=0

We add all the numbers together, and all the variables

z-3=0

We move all terms containing z to the left, all other terms to the right

z=3

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