3(2z+)=6(5z+2)

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Solution for 3(2z+)=6(5z+2) equation: 



3(2z+)=6(5z+2)

We move all terms to the left:

3(2z+)-(6(5z+2))=0

We add all the numbers together, and all the variables

3(+2z)-(6(5z+2))=0

We multiply parentheses

6z-(6(5z+2))=0



We calculate terms in parentheses: -(6(5z+2)), so:

6(5z+2)

We multiply parentheses

30z+12

Back to the equation:

-(30z+12)



We get rid of parentheses

6z-30z-12=0

We add all the numbers together, and all the variables

-24z-12=0

We move all terms containing z to the left, all other terms to the right

-24z=12

z=12/-24

z=-1/2

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