3(2y-5)=32

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Solution for 3(2y-5)=32 equation:



3(2y-5)=32
We move all terms to the left:
3(2y-5)-(32)=0
We multiply parentheses
6y-15-32=0
We add all the numbers together, and all the variables
6y-47=0
We move all terms containing y to the left, all other terms to the right
6y=47
y=47/6
y=7+5/6

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