3(2y-5)=-27

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Solution for 3(2y-5)=-27 equation: 



3(2y-5)=-27

We move all terms to the left:

3(2y-5)-(-27)=0

We add all the numbers together, and all the variables

3(2y-5)+27=0

We multiply parentheses

6y-15+27=0

We add all the numbers together, and all the variables

6y+12=0

We move all terms containing y to the left, all other terms to the right

6y=-12

y=-12/6

y=-2

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