3(2y-4)=4(y+7)-2

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Solution for 3(2y-4)=4(y+7)-2 equation: 



3(2y-4)=4(y+7)-2

We move all terms to the left:

3(2y-4)-(4(y+7)-2)=0

We multiply parentheses

6y-(4(y+7)-2)-12=0



We calculate terms in parentheses: -(4(y+7)-2), so:

4(y+7)-2

We multiply parentheses

4y+28-2

We add all the numbers together, and all the variables

4y+26

Back to the equation:

-(4y+26)



We get rid of parentheses

6y-4y-26-12=0

We add all the numbers together, and all the variables

2y-38=0

We move all terms containing y to the left, all other terms to the right

2y=38

y=38/2

y=19

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