3(2y-4)-8y=6

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Solution for 3(2y-4)-8y=6 equation: 



3(2y-4)-8y=6

We move all terms to the left:

3(2y-4)-8y-(6)=0

We add all the numbers together, and all the variables

-8y+3(2y-4)-6=0

We multiply parentheses

-8y+6y-12-6=0

We add all the numbers together, and all the variables

-2y-18=0

We move all terms containing y to the left, all other terms to the right

-2y=18

y=18/-2

y=-9

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