3(2y-4)-2(y+1)=10

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Solution for 3(2y-4)-2(y+1)=10 equation: 


Simplifying
3(2y + -4) + -2(y + 1) = 10

Reorder the terms:
3(-4 + 2y) + -2(y + 1) = 10
(-4 * 3 + 2y * 3) + -2(y + 1) = 10
(-12 + 6y) + -2(y + 1) = 10

Reorder the terms:
-12 + 6y + -2(1 + y) = 10
-12 + 6y + (1 * -2 + y * -2) = 10
-12 + 6y + (-2 + -2y) = 10

Reorder the terms:
-12 + -2 + 6y + -2y = 10

Combine like terms: -12 + -2 = -14
-14 + 6y + -2y = 10

Combine like terms: 6y + -2y = 4y
-14 + 4y = 10

Solving
-14 + 4y = 10

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + 4y = 10 + 14

Combine like terms: -14 + 14 = 0
0 + 4y = 10 + 14
4y = 10 + 14

Combine like terms: 10 + 14 = 24
4y = 24

Divide each side by '4'.
y = 6

Simplifying
y = 6

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