3(2y-4)+8=10y-7

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Solution for 3(2y-4)+8=10y-7 equation: 



3(2y-4)+8=10y-7

We move all terms to the left:

3(2y-4)+8-(10y-7)=0

We multiply parentheses

6y-(10y-7)-12+8=0

We get rid of parentheses

6y-10y+7-12+8=0

We add all the numbers together, and all the variables

-4y+3=0

We move all terms containing y to the left, all other terms to the right

-4y=-3

y=-3/-4

y=3/4

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