3(2y-4)+3y=5(y-4)

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Solution for 3(2y-4)+3y=5(y-4) equation: 



3(2y-4)+3y=5(y-4)

We move all terms to the left:

3(2y-4)+3y-(5(y-4))=0

We add all the numbers together, and all the variables

3y+3(2y-4)-(5(y-4))=0

We multiply parentheses

3y+6y-(5(y-4))-12=0



We calculate terms in parentheses: -(5(y-4)), so:

5(y-4)

We multiply parentheses

5y-20

Back to the equation:

-(5y-20)



We add all the numbers together, and all the variables

9y-(5y-20)-12=0

We get rid of parentheses

9y-5y+20-12=0

We add all the numbers together, and all the variables

4y+8=0

We move all terms containing y to the left, all other terms to the right

4y=-8

y=-8/4

y=-2

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