3(2y-3)=5(y+2)-19

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Solution for 3(2y-3)=5(y+2)-19 equation:



3(2y-3)=5(y+2)-19
We move all terms to the left:
3(2y-3)-(5(y+2)-19)=0
We multiply parentheses
6y-(5(y+2)-19)-9=0
We calculate terms in parentheses: -(5(y+2)-19), so:
5(y+2)-19
We multiply parentheses
5y+10-19
We add all the numbers together, and all the variables
5y-9
Back to the equation:
-(5y-9)
We get rid of parentheses
6y-5y+9-9=0
We add all the numbers together, and all the variables
y=0

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