3(2y-3)=4(6y+7)=

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Solution for 3(2y-3)=4(6y+7)= equation: 



3(2y-3)=4(6y+7)=

We move all terms to the left:

3(2y-3)-(4(6y+7))=0

We multiply parentheses

6y-(4(6y+7))-9=0



We calculate terms in parentheses: -(4(6y+7)), so:

4(6y+7)

We multiply parentheses

24y+28

Back to the equation:

-(24y+28)



We get rid of parentheses

6y-24y-28-9=0

We add all the numbers together, and all the variables

-18y-37=0

We move all terms containing y to the left, all other terms to the right

-18y=37

y=37/-18

y=-2+1/18

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