3(2y-2)+4y+16=3

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Solution for 3(2y-2)+4y+16=3 equation: 



3(2y-2)+4y+16=3

We move all terms to the left:

3(2y-2)+4y+16-(3)=0

We add all the numbers together, and all the variables

4y+3(2y-2)+13=0

We multiply parentheses

4y+6y-6+13=0

We add all the numbers together, and all the variables

10y+7=0

We move all terms containing y to the left, all other terms to the right

10y=-7

y=-7/10

y=-7/10

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