3(2y-10)=(4y-7)/2

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Solution for 3(2y-10)=(4y-7)/2 equation:



3(2y-10)=(4y-7)/2
We move all terms to the left:
3(2y-10)-((4y-7)/2)=0
We multiply parentheses
6y-((4y-7)/2)-30=0
We multiply all the terms by the denominator
6y*2)-((4y-7)-30*2)=0
We add all the numbers together, and all the variables
6y*2)-((4y-7)=0
Wy multiply elements
12y^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{24}=0$

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