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3(2y-1)=4-2(y-3)
We move all terms to the left:
3(2y-1)-(4-2(y-3))=0
We multiply parentheses
6y-(4-2(y-3))-3=0
We calculate terms in parentheses: -(4-2(y-3)), so:We get rid of parentheses
4-2(y-3)
determiningTheFunctionDomain -2(y-3)+4
We multiply parentheses
-2y+6+4
We add all the numbers together, and all the variables
-2y+10
Back to the equation:
-(-2y+10)
6y+2y-10-3=0
We add all the numbers together, and all the variables
8y-13=0
We move all terms containing y to the left, all other terms to the right
8y=13
y=13/8
y=1+5/8
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