3(2y-1)=39-2(y+1)

Solution for 3(2y-1)=39-2(y+1) equation:

3(2y-1)=39-2(y+1)

We move all terms to the left:

3(2y-1)-(39-2(y+1))=0

We multiply parentheses

6y-(39-2(y+1))-3=0


We calculate terms in parentheses: -(39-2(y+1)), so:

39-2(y+1)

determiningTheFunctionDomain
-2(y+1)+39

We multiply parentheses

-2y-2+39

We add all the numbers together, and all the variables

-2y+37

Back to the equation:

-(-2y+37)


We get rid of parentheses

6y+2y-37-3=0

We add all the numbers together, and all the variables

8y-40=0

We move all terms containing y to the left, all other terms to the right

8y=40

y=40/8

y=5