3(2y+4)=-2(7y-6)

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Solution for 3(2y+4)=-2(7y-6) equation: 



3(2y+4)=-2(7y-6)

We move all terms to the left:

3(2y+4)-(-2(7y-6))=0

We multiply parentheses

6y-(-2(7y-6))+12=0



We calculate terms in parentheses: -(-2(7y-6)), so:

-2(7y-6)

We multiply parentheses

-14y+12

Back to the equation:

-(-14y+12)



We get rid of parentheses

6y+14y-12+12=0

We add all the numbers together, and all the variables

20y=0

y=0/20

y=0

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