3(2y+1)=8y-5

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Solution for 3(2y+1)=8y-5 equation: 



3(2y+1)=8y-5

We move all terms to the left:

3(2y+1)-(8y-5)=0

We multiply parentheses

6y-(8y-5)+3=0

We get rid of parentheses

6y-8y+5+3=0

We add all the numbers together, and all the variables

-2y+8=0

We move all terms containing y to the left, all other terms to the right

-2y=-8

y=-8/-2

y=+4

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