3(2y+1)=6(y-2)+15

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Solution for 3(2y+1)=6(y-2)+15 equation: 


Simplifying
3(2y + 1) = 6(y + -2) + 15

Reorder the terms:
3(1 + 2y) = 6(y + -2) + 15
(1 * 3 + 2y * 3) = 6(y + -2) + 15
(3 + 6y) = 6(y + -2) + 15

Reorder the terms:
3 + 6y = 6(-2 + y) + 15
3 + 6y = (-2 * 6 + y * 6) + 15
3 + 6y = (-12 + 6y) + 15

Reorder the terms:
3 + 6y = -12 + 15 + 6y

Combine like terms: -12 + 15 = 3
3 + 6y = 3 + 6y

Add '-3' to each side of the equation.
3 + -3 + 6y = 3 + -3 + 6y

Combine like terms: 3 + -3 = 0
0 + 6y = 3 + -3 + 6y
6y = 3 + -3 + 6y

Combine like terms: 3 + -3 = 0
6y = 0 + 6y
6y = 6y

Add '-6y' to each side of the equation.
6y + -6y = 6y + -6y

Combine like terms: 6y + -6y = 0
0 = 6y + -6y

Combine like terms: 6y + -6y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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