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3(2y+1)=5(y+5)
We move all terms to the left:
3(2y+1)-(5(y+5))=0
We multiply parentheses
6y-(5(y+5))+3=0
We calculate terms in parentheses: -(5(y+5)), so:We get rid of parentheses
5(y+5)
We multiply parentheses
5y+25
Back to the equation:
-(5y+25)
6y-5y-25+3=0
We add all the numbers together, and all the variables
y-22=0
We move all terms containing y to the left, all other terms to the right
y=22
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