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3(2y+1)=2(9-y)
We move all terms to the left:
3(2y+1)-(2(9-y))=0
We add all the numbers together, and all the variables
3(2y+1)-(2(-1y+9))=0
We multiply parentheses
6y-(2(-1y+9))+3=0
We calculate terms in parentheses: -(2(-1y+9)), so:We get rid of parentheses
2(-1y+9)
We multiply parentheses
-2y+18
Back to the equation:
-(-2y+18)
6y+2y-18+3=0
We add all the numbers together, and all the variables
8y-15=0
We move all terms containing y to the left, all other terms to the right
8y=15
y=15/8
y=1+7/8
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