3(2y+1)=-3(3y+4)

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Solution for 3(2y+1)=-3(3y+4) equation: 



3(2y+1)=-3(3y+4)

We move all terms to the left:

3(2y+1)-(-3(3y+4))=0

We multiply parentheses

6y-(-3(3y+4))+3=0



We calculate terms in parentheses: -(-3(3y+4)), so:

-3(3y+4)

We multiply parentheses

-9y-12

Back to the equation:

-(-9y-12)



We get rid of parentheses

6y+9y+12+3=0

We add all the numbers together, and all the variables

15y+15=0

We move all terms containing y to the left, all other terms to the right

15y=-15

y=-15/15

y=-1

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