3(2y+1)=-2(3y+4)

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Solution for 3(2y+1)=-2(3y+4) equation: 



3(2y+1)=-2(3y+4)

We move all terms to the left:

3(2y+1)-(-2(3y+4))=0

We multiply parentheses

6y-(-2(3y+4))+3=0



We calculate terms in parentheses: -(-2(3y+4)), so:

-2(3y+4)

We multiply parentheses

-6y-8

Back to the equation:

-(-6y-8)



We get rid of parentheses

6y+6y+8+3=0

We add all the numbers together, and all the variables

12y+11=0

We move all terms containing y to the left, all other terms to the right

12y=-11

y=-11/12

y=-11/12

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