3(2x-9)=8(x-12)+29

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Solution for 3(2x-9)=8(x-12)+29 equation: 



3(2x-9)=8(x-12)+29

We move all terms to the left:

3(2x-9)-(8(x-12)+29)=0

We multiply parentheses

6x-(8(x-12)+29)-27=0



We calculate terms in parentheses: -(8(x-12)+29), so:

8(x-12)+29

We multiply parentheses

8x-96+29

We add all the numbers together, and all the variables

8x-67

Back to the equation:

-(8x-67)



We get rid of parentheses

6x-8x+67-27=0

We add all the numbers together, and all the variables

-2x+40=0

We move all terms containing x to the left, all other terms to the right

-2x=-40

x=-40/-2

x=+20

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