3(2x-8)+4(x+2)=16

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Solution for 3(2x-8)+4(x+2)=16 equation: 



3(2x-8)+4(x+2)=16

We move all terms to the left:

3(2x-8)+4(x+2)-(16)=0

We multiply parentheses

6x+4x-24+8-16=0

We add all the numbers together, and all the variables

10x-32=0

We move all terms containing x to the left, all other terms to the right

10x=32

x=32/10

x=3+1/5

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