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3(2x-5)=7*5-(4x-5)
We move all terms to the left:
3(2x-5)-(7*5-(4x-5))=0
We multiply parentheses
6x-(7*5-(4x-5))-15=0
We calculate terms in parentheses: -(7*5-(4x-5)), so:We get rid of parentheses
7*5-(4x-5)
determiningTheFunctionDomain -(4x-5)+7*5
We add all the numbers together, and all the variables
-(4x-5)+35
We get rid of parentheses
-4x+5+35
We add all the numbers together, and all the variables
-4x+40
Back to the equation:
-(-4x+40)
6x+4x-40-15=0
We add all the numbers together, and all the variables
10x-55=0
We move all terms containing x to the left, all other terms to the right
10x=55
x=55/10
x=5+1/2
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