3(2x-5)=7(2x-10)+5

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Solution for 3(2x-5)=7(2x-10)+5 equation: 



3(2x-5)=7(2x-10)+5

We move all terms to the left:

3(2x-5)-(7(2x-10)+5)=0

We multiply parentheses

6x-(7(2x-10)+5)-15=0



We calculate terms in parentheses: -(7(2x-10)+5), so:

7(2x-10)+5

We multiply parentheses

14x-70+5

We add all the numbers together, and all the variables

14x-65

Back to the equation:

-(14x-65)



We get rid of parentheses

6x-14x+65-15=0

We add all the numbers together, and all the variables

-8x+50=0

We move all terms containing x to the left, all other terms to the right

-8x=-50

x=-50/-8

x=6+1/4

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