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3(2x-5)=5(x-4)+x=5
We move all terms to the left:
3(2x-5)-(5(x-4)+x)=0
We multiply parentheses
6x-(5(x-4)+x)-15=0
We calculate terms in parentheses: -(5(x-4)+x), so:We get rid of parentheses
5(x-4)+x
We add all the numbers together, and all the variables
x+5(x-4)
We multiply parentheses
x+5x-20
We add all the numbers together, and all the variables
6x-20
Back to the equation:
-(6x-20)
6x-6x+20-15=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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