3(2x-5)=5(x-4)+5+x

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Solution for 3(2x-5)=5(x-4)+5+x equation: 



3(2x-5)=5(x-4)+5+x

We move all terms to the left:

3(2x-5)-(5(x-4)+5+x)=0

We multiply parentheses

6x-(5(x-4)+5+x)-15=0



We calculate terms in parentheses: -(5(x-4)+5+x), so:

5(x-4)+5+x

determiningTheFunctionDomain
5(x-4)+x+5

We add all the numbers together, and all the variables

x+5(x-4)+5

We multiply parentheses

x+5x-20+5

We add all the numbers together, and all the variables

6x-15

Back to the equation:

-(6x-15)



We get rid of parentheses

6x-6x+15-15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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