3(2x-5)=4(x-2)+1

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Solution for 3(2x-5)=4(x-2)+1 equation: 



3(2x-5)=4(x-2)+1

We move all terms to the left:

3(2x-5)-(4(x-2)+1)=0

We multiply parentheses

6x-(4(x-2)+1)-15=0



We calculate terms in parentheses: -(4(x-2)+1), so:

4(x-2)+1

We multiply parentheses

4x-8+1

We add all the numbers together, and all the variables

4x-7

Back to the equation:

-(4x-7)



We get rid of parentheses

6x-4x+7-15=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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