3(2x-5)=-5(x-4)+x

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Solution for 3(2x-5)=-5(x-4)+x equation: 



3(2x-5)=-5(x-4)+x

We move all terms to the left:

3(2x-5)-(-5(x-4)+x)=0

We multiply parentheses

6x-(-5(x-4)+x)-15=0



We calculate terms in parentheses: -(-5(x-4)+x), so:

-5(x-4)+x

We add all the numbers together, and all the variables

x-5(x-4)

We multiply parentheses

x-5x+20

We add all the numbers together, and all the variables

-4x+20

Back to the equation:

-(-4x+20)



We get rid of parentheses

6x+4x-20-15=0

We add all the numbers together, and all the variables

10x-35=0

We move all terms containing x to the left, all other terms to the right

10x=35

x=35/10

x=3+1/2

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