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3(2x-5)=+4(3x+2)
We move all terms to the left:
3(2x-5)-(+4(3x+2))=0
We multiply parentheses
6x-(+4(3x+2))-15=0
We calculate terms in parentheses: -(+4(3x+2)), so:We get rid of parentheses
+4(3x+2)
determiningTheFunctionDomain 4(3x+2)
We multiply parentheses
12x+8
Back to the equation:
-(12x+8)
6x-12x-8-15=0
We add all the numbers together, and all the variables
-6x-23=0
We move all terms containing x to the left, all other terms to the right
-6x=23
x=23/-6
x=-3+5/6
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