3(2x-5)=(x-8)+3

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Solution for 3(2x-5)=(x-8)+3 equation: 



3(2x-5)=(x-8)+3

We move all terms to the left:

3(2x-5)-((x-8)+3)=0

We multiply parentheses

6x-((x-8)+3)-15=0



We calculate terms in parentheses: -((x-8)+3), so:

(x-8)+3

We get rid of parentheses

x-8+3

We add all the numbers together, and all the variables

x-5

Back to the equation:

-(x-5)



We get rid of parentheses

6x-x+5-15=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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