3(2x-5)/8=7x+3/3

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Solution for 3(2x-5)/8=7x+3/3 equation: 



3(2x-5)/8=7x+3/3

We move all terms to the left:

3(2x-5)/8-(7x+3/3)=0

We add all the numbers together, and all the variables

3(2x-5)/8-(7x+1)=0

We get rid of parentheses

3(2x-5)/8-7x-1=0

We multiply all the terms by the denominator


3(2x-5)-7x*8-1*8=0

We add all the numbers together, and all the variables

3(2x-5)-7x*8-8=0

We multiply parentheses

6x-7x*8-15-8=0

Wy multiply elements

6x-56x-15-8=0

We add all the numbers together, and all the variables

-50x-23=0

We move all terms containing x to the left, all other terms to the right

-50x=23

x=23/-50

x=-23/50

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