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3(2x-5)-2(4x-3)+3(-x+2)=-4(-2x+3)+3(-2x-2)-6(3x+3)
We move all terms to the left:
3(2x-5)-2(4x-3)+3(-x+2)-(-4(-2x+3)+3(-2x-2)-6(3x+3))=0
We add all the numbers together, and all the variables
3(2x-5)-2(4x-3)+3(-1x+2)-(-4(-2x+3)+3(-2x-2)-6(3x+3))=0
We multiply parentheses
6x-8x-3x-(-4(-2x+3)+3(-2x-2)-6(3x+3))-15+6+6=0
We calculate terms in parentheses: -(-4(-2x+3)+3(-2x-2)-6(3x+3)), so:We add all the numbers together, and all the variables
-4(-2x+3)+3(-2x-2)-6(3x+3)
We multiply parentheses
8x-6x-18x-12-6-18
We add all the numbers together, and all the variables
-16x-36
Back to the equation:
-(-16x-36)
-5x-(-16x-36)-3=0
We get rid of parentheses
-5x+16x+36-3=0
We add all the numbers together, and all the variables
11x+33=0
We move all terms containing x to the left, all other terms to the right
11x=-33
x=-33/11
x=-3
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