3(2x-5)-2(4x+1)=-5(x+3)-26x-15-8x-2

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Solution for 3(2x-5)-2(4x+1)=-5(x+3)-26x-15-8x-2 equation: 



3(2x-5)-2(4x+1)=-5(x+3)-26x-15-8x-2

We move all terms to the left:

3(2x-5)-2(4x+1)-(-5(x+3)-26x-15-8x-2)=0

We multiply parentheses

6x-8x-(-5(x+3)-26x-15-8x-2)-15-2=0



We calculate terms in parentheses: -(-5(x+3)-26x-15-8x-2), so:

-5(x+3)-26x-15-8x-2

determiningTheFunctionDomain
-5(x+3)-26x-8x-15-2

We add all the numbers together, and all the variables

-34x-5(x+3)-17

We multiply parentheses

-34x-5x-15-17

We add all the numbers together, and all the variables

-39x-32

Back to the equation:

-(-39x-32)



We add all the numbers together, and all the variables

-2x-(-39x-32)-17=0

We get rid of parentheses

-2x+39x+32-17=0

We add all the numbers together, and all the variables

37x+15=0

We move all terms containing x to the left, all other terms to the right

37x=-15

x=-15/37

x=-15/37

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