3(2x-5)+x=4x-1-2(x+2)

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Solution for 3(2x-5)+x=4x-1-2(x+2) equation: 



3(2x-5)+x=4x-1-2(x+2)

We move all terms to the left:

3(2x-5)+x-(4x-1-2(x+2))=0

We add all the numbers together, and all the variables

x+3(2x-5)-(4x-1-2(x+2))=0

We multiply parentheses

x+6x-(4x-1-2(x+2))-15=0



We calculate terms in parentheses: -(4x-1-2(x+2)), so:

4x-1-2(x+2)

determiningTheFunctionDomain
4x-2(x+2)-1

We multiply parentheses

4x-2x-4-1

We add all the numbers together, and all the variables

2x-5

Back to the equation:

-(2x-5)



We add all the numbers together, and all the variables

7x-(2x-5)-15=0

We get rid of parentheses

7x-2x+5-15=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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