3(2x-5)+6(x-5)=-3(3-5x)+5x-26

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Solution for 3(2x-5)+6(x-5)=-3(3-5x)+5x-26 equation: 



3(2x-5)+6(x-5)=-3(3-5x)+5x-26

We move all terms to the left:

3(2x-5)+6(x-5)-(-3(3-5x)+5x-26)=0

We add all the numbers together, and all the variables

3(2x-5)+6(x-5)-(-3(-5x+3)+5x-26)=0

We multiply parentheses

6x+6x-(-3(-5x+3)+5x-26)-15-30=0



We calculate terms in parentheses: -(-3(-5x+3)+5x-26), so:

-3(-5x+3)+5x-26

We add all the numbers together, and all the variables

5x-3(-5x+3)-26

We multiply parentheses

5x+15x-9-26

We add all the numbers together, and all the variables

20x-35

Back to the equation:

-(20x-35)



We add all the numbers together, and all the variables

12x-(20x-35)-45=0

We get rid of parentheses

12x-20x+35-45=0

We add all the numbers together, and all the variables

-8x-10=0

We move all terms containing x to the left, all other terms to the right

-8x=10

x=10/-8

x=-1+1/4

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