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3(2x-5)+5=(3x+6)
We move all terms to the left:
3(2x-5)+5-((3x+6))=0
We multiply parentheses
6x-((3x+6))-15+5=0
We calculate terms in parentheses: -((3x+6)), so:We add all the numbers together, and all the variables
(3x+6)
We get rid of parentheses
3x+6
Back to the equation:
-(3x+6)
6x-(3x+6)-10=0
We get rid of parentheses
6x-3x-6-10=0
We add all the numbers together, and all the variables
3x-16=0
We move all terms containing x to the left, all other terms to the right
3x=16
x=16/3
x=5+1/3
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