3(2x-5)+4(x-2)=17

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Solution for 3(2x-5)+4(x-2)=17 equation: 



3(2x-5)+4(x-2)=17

We move all terms to the left:

3(2x-5)+4(x-2)-(17)=0

We multiply parentheses

6x+4x-15-8-17=0

We add all the numbers together, and all the variables

10x-40=0

We move all terms containing x to the left, all other terms to the right

10x=40

x=40/10

x=4

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