3(2x-4)=5(x-3)+12

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Solution for 3(2x-4)=5(x-3)+12 equation: 



3(2x-4)=5(x-3)+12

We move all terms to the left:

3(2x-4)-(5(x-3)+12)=0

We multiply parentheses

6x-(5(x-3)+12)-12=0



We calculate terms in parentheses: -(5(x-3)+12), so:

5(x-3)+12

We multiply parentheses

5x-15+12

We add all the numbers together, and all the variables

5x-3

Back to the equation:

-(5x-3)



We get rid of parentheses

6x-5x+3-12=0

We add all the numbers together, and all the variables

x-9=0

We move all terms containing x to the left, all other terms to the right

x=9

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