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3(2x-4)=5(x+3)+9
We move all terms to the left:
3(2x-4)-(5(x+3)+9)=0
We multiply parentheses
6x-(5(x+3)+9)-12=0
We calculate terms in parentheses: -(5(x+3)+9), so:We get rid of parentheses
5(x+3)+9
We multiply parentheses
5x+15+9
We add all the numbers together, and all the variables
5x+24
Back to the equation:
-(5x+24)
6x-5x-24-12=0
We add all the numbers together, and all the variables
x-36=0
We move all terms containing x to the left, all other terms to the right
x=36
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