3(2x-4)=4x+20

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Solution for 3(2x-4)=4x+20 equation: 



3(2x-4)=4x+20

We move all terms to the left:

3(2x-4)-(4x+20)=0

We multiply parentheses

6x-(4x+20)-12=0

We get rid of parentheses

6x-4x-20-12=0

We add all the numbers together, and all the variables

2x-32=0

We move all terms containing x to the left, all other terms to the right

2x=32

x=32/2

x=16

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