3(2x-4)=37-5(x+1)

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Solution for 3(2x-4)=37-5(x+1) equation: 



3(2x-4)=37-5(x+1)

We move all terms to the left:

3(2x-4)-(37-5(x+1))=0

We multiply parentheses

6x-(37-5(x+1))-12=0



We calculate terms in parentheses: -(37-5(x+1)), so:

37-5(x+1)

determiningTheFunctionDomain
-5(x+1)+37

We multiply parentheses

-5x-5+37

We add all the numbers together, and all the variables

-5x+32

Back to the equation:

-(-5x+32)



We get rid of parentheses

6x+5x-32-12=0

We add all the numbers together, and all the variables

11x-44=0

We move all terms containing x to the left, all other terms to the right

11x=44

x=44/11

x=4

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