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3(2x-4)=-2(1+x)
We move all terms to the left:
3(2x-4)-(-2(1+x))=0
We add all the numbers together, and all the variables
3(2x-4)-(-2(x+1))=0
We multiply parentheses
6x-(-2(x+1))-12=0
We calculate terms in parentheses: -(-2(x+1)), so:We get rid of parentheses
-2(x+1)
We multiply parentheses
-2x-2
Back to the equation:
-(-2x-2)
6x+2x+2-12=0
We add all the numbers together, and all the variables
8x-10=0
We move all terms containing x to the left, all other terms to the right
8x=10
x=10/8
x=1+1/4
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