3(2x-4)=(-4x)+28

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Solution for 3(2x-4)=(-4x)+28 equation: 



3(2x-4)=(-4x)+28

We move all terms to the left:

3(2x-4)-((-4x)+28)=0

We multiply parentheses

6x-((-4x)+28)-12=0



We calculate terms in parentheses: -((-4x)+28), so:

(-4x)+28

We get rid of parentheses

-4x+28

Back to the equation:

-(-4x+28)



We get rid of parentheses

6x+4x-28-12=0

We add all the numbers together, and all the variables

10x-40=0

We move all terms containing x to the left, all other terms to the right

10x=40

x=40/10

x=4

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