3(2x-3)=5(7x-2)

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Solution for 3(2x-3)=5(7x-2) equation: 



3(2x-3)=5(7x-2)

We move all terms to the left:

3(2x-3)-(5(7x-2))=0

We multiply parentheses

6x-(5(7x-2))-9=0



We calculate terms in parentheses: -(5(7x-2)), so:

5(7x-2)

We multiply parentheses

35x-10

Back to the equation:

-(35x-10)



We get rid of parentheses

6x-35x+10-9=0

We add all the numbers together, and all the variables

-29x+1=0

We move all terms containing x to the left, all other terms to the right

-29x=-1

x=-1/-29

x=1/29

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