3(2x-3)=2(3x-2)

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Solution for 3(2x-3)=2(3x-2) equation: 



3(2x-3)=2(3x-2)

We move all terms to the left:

3(2x-3)-(2(3x-2))=0

We multiply parentheses

6x-(2(3x-2))-9=0



We calculate terms in parentheses: -(2(3x-2)), so:

2(3x-2)

We multiply parentheses

6x-4

Back to the equation:

-(6x-4)



We get rid of parentheses

6x-6x+4-9=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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