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3(2x-3)=2(3x+1)-11
We move all terms to the left:
3(2x-3)-(2(3x+1)-11)=0
We multiply parentheses
6x-(2(3x+1)-11)-9=0
We calculate terms in parentheses: -(2(3x+1)-11), so:We get rid of parentheses
2(3x+1)-11
We multiply parentheses
6x+2-11
We add all the numbers together, and all the variables
6x-9
Back to the equation:
-(6x-9)
6x-6x+9-9=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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