3(2x-3)-5=3(x-5)+19

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Solution for 3(2x-3)-5=3(x-5)+19 equation: 



3(2x-3)-5=3(x-5)+19

We move all terms to the left:

3(2x-3)-5-(3(x-5)+19)=0

We multiply parentheses

6x-(3(x-5)+19)-9-5=0



We calculate terms in parentheses: -(3(x-5)+19), so:

3(x-5)+19

We multiply parentheses

3x-15+19

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We add all the numbers together, and all the variables

6x-(3x+4)-14=0

We get rid of parentheses

6x-3x-4-14=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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